错在那里
.net
Sub transform(ByVal arg As String)
arg = "/check/unit[@name='a']"
Dim byunit As Object = arg
MsgBox(byunit)
Dim args As New XsltArgumentList
Try
args.AddParam("byunit", "", byunit)
Catch ex As Exception
MsgBox("error:" & ex.Message & ex.Source & ex.InnerException.ToString)
End Try
Dim xmldoc As New XmlDocument
xmldoc.Load("check.xml")
Dim xmlnavi As XPathNavigator
xmlnavi = xmldoc.CreateNavigator
Dim filestream As FileStream = New FileStream("check.html", FileMode.Create)
Dim mytransform As New XslTransform
Try
mytransform.Load("checkprint.xslt", Nothing)
'mytransform.Transform("F:\windowstry\lawcheck\check.xml", "F:\windowstry\lawcheck\check.htm", Nothing)
mytransform.Transform(xmlnavi, args, filestream, Nothing)
MsgBox(args.GetType.ToString & args.GetParam("byunit", Nothing).ToString)
Catch ex As Exception
MsgBox("error:" & ex.Message & ex.Source)
Exit Sub
End Try
filestream.Close()
MsgBox("successful")
end sub
xslt: check.xslt
<?xml version="1.0" encoding="gb2312" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:param name="byunit" ></xsl:param>
<html>
<head><title></title></head>
<body>
<div>aaa</div>
<p></p>
<xsl:for-each select="$byunit">
<xsl:call-template name="showcheck">
<xsl:with-param name="thischeckname" select="item[@checkname='a']" ></xsl:with-param>
</xsl:call-template>
<xsl:call-template name="showcheck">
<xsl:with-param name="thischeckname" select="item[@checkname='b']" ></xsl:with-param>
</xsl:call-template>
</xsl:for-each>
</body>
</html>
</xsl:template>
<xsl:template name="showcheck">
<xsl:param name="thischeckname" select="check/unit/item"></xsl:param>
<xsl:for-each select="$thischeckname">
<div style="TEXT-INDENT: 20px; TEXT-ALIGN: left"><xsl:value-of select="@checkname"></xsl:value-of>：</div>
<div style="TEXT-INDENT: 50px; TEXT-ALIGN: left"><xsl:value-of select="comment"></xsl:value-of></div>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
出错“传递此方法的表达式应产生nodeset” 错在那里请赐教
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2005/10/15 20:30:00
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能不能用vb.net向xslt传参数？
