-- 发布时间：8/23/2005 2:01:00 PM
-- xml+xslt问题:不能正常显示
student.xml
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="mystyle.xsl"?>
<roster>
The roster of the students
<student>
<name>Li Hua</name>
<origin>He Bei</origin>
<age>15</age>
<telephone>325242352</telephone>
</student>
<student>
<name>Zhang San</name>
<origin>Bei Jing</origin>
<age>15</age>
<telephone>6457464</telephone>
</student>
</roster>
mystyle.xsl
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns="http://www.w3.org/TR/REC-html40">
<xsl:template>
<xsl:apply-templates />
</xsl:template>
<xsl:template match="/">
<html>
<head>
<title>Memberlist Of Student</title>
<style>
.title{font-size:15pt; font-weight:bold; color:blue}
.name {color:red}
</style>
</head>
<body>
<p class="title">Memberlist Of Student</p>
<xsl:apply-templates select="roster"/>
</body>
</html>
</xsl:template>
<xsl:template match="roster">
<table border="1">
<thead>
<td><b>name</b></td>
<td><b>origin</b></td>
<td><b>age</b></td>
<td><b>telephone</b></td>
</thead>
<xsl:for-each select="student" order-by="name">
<tr>
<td><b><xsl:value-of select="name"/></b></td>
<td><b><xsl:value-of select="origin"/></b></td>
<td><b><xsl:value-of select="age"/></b></td>
<td><b><xsl:value-of select="telephone"/></b></td>
</tr>
</xsl:for-each>
</table>
</xsl:template>
</xsl:stylesheet>
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可是当我浏览的时候 提示:
The XML page cannot be displayed
Cannot view XML input using XSL style sheet. Please correct the error and then click the Refresh button, or try again later.
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Required attribute 'version' is missing.
晕啊,啥原因呢???哥哥们帮忙
