以文本方式查看主题

-  计算机科学论坛  (http://bbs.xml.org.cn/index.asp)
--  『 理论计算机科学 』  (http://bbs.xml.org.cn/list.asp?boardid=64)
----  Let's have a fun way to learn Conditional Probabilities and Bayes' Theorem  (http://bbs.xml.org.cn/dispbbs.asp?boardid=64&rootid=&id=24094)


--  作者:stillthere
--  发布时间:11/9/2005 11:19:00 AM

--  Let's have a fun way to learn Conditional Probabilities and Bayes' Theorem

Here's a story problem about a situation that doctors often encounter:


1% of women at age forty who participate in routine screening have breast cancer.  80% of women with breast cancer will get positive mammographies.  9.6% of women without breast cancer will also get positive mammographies.  A woman in this age group had a positive mammography in a routine screening.  What is the probability that she actually has breast cancer?


What do you think the answer is?  If you haven't encountered this kind of problem before, please take a moment to come up with your own answer before continuing.


http://yudkowsky.net/bayes/bayes.html


[此贴子已经被作者于2005-11-9 22:59:01编辑过]

--  作者:arcong
--  发布时间:11/25/2005 12:10:00 AM

--  
80% of women with breast cancer will get positive mammographies thus 20% women wont..
9.6% of women without cancer will have positive thus 93.4% of them wont have ...

it should be clear if we simply draw the diagram to represent the relationship...

             80% have cancer  ( positive)      
1%  ----<
             20% have cancer   (nagative)

      
             9.6% no cancer ( positive)
99%----<
             93.4% no cancer ( nagative)

then ? whats next >? I got confused ...

if the result is positive... she has 0.01*0.08 / ( 0.01*0.08 + 0.99*0.096)
.. am I right ? almost the conditional probability ...


--  作者:stillthere
--  发布时间:11/28/2005 10:16:00 PM

--  
Don't get confused.

If you keep reading on that website you will have a very clear picture.


W 3 C h i n a ( since 2003 ) 旗 下 站 点
苏ICP备05006046号《全国人大常委会关于维护互联网安全的决定》《计算机信息网络国际联网安全保护管理办法》
46.875ms